Higher June 2018 Paper 1R Q6
6
Diagram NOT accurately drawn
\(ABC\) and \(DEF\) are parallel lines.
\(BG = BE\)
Angle \(DEG = 38°\)
Angle \(GEB = 65°\)
Find the size of angle \(ABG\).
(3)
| Scheme | Marks |
|---|---|
| Angle \(EBG\) = 180 – 2 × 65 (= 50) or Angle \(ABE\) = 180 − (38 + 65) (= 77) | M1 |
| Angle \(ABE\) = 180 − (38 + 65) (= 77) and Angle \(ABG\) = “77” – “50” | M1 |
| 27 | A1 |
| (3) | |
| (3 marks) |
Notes
M1: for a complete method to find angle \(ABG\)
| Scheme | Marks |
|---|---|
| Angle \(EBG\) = 180 – 2 × 65 (= 50) or Angle \(EBC\) = 103 | M1 |
| Angle \(EBC\) = 103 and Angle \(ABG\) = 180 – (103 + “50”) | M1 |
| 27 | A1 |
Notes
M1: for a complete method to find angle \(ABG\)