Higher January 2020 Paper 2R Q20
20 The diagram shows two similar vases, A and B.
Diagram NOT accurately drawn
The height of vase A is 9 cm and the height of vase B is 13 cm.
Given that
surface area of vase A + surface area of vase B = 1800 cm²
calculate the surface area of vase A.
(4)
| Scheme | Marks |
|---|---|
| (ASF =) \(\dfrac{13^2}{9^2}\) or \(\dfrac{9^2}{13^2}\) | M1 |
| eg \(A + \text{“}\left(\dfrac{13^2}{9^2}\right)\text{”}A = 1800\) | M1ft |
| eg \(\text{“}\dfrac{250}{81}\text{”}A = 1800\) | M1ft |
| 583.2 | A1 |
| (4) | |
| (4 marks) |
Notes
M1: Correct SF for area.
Accept \(1.44^2\) (= 2.07 or 2.09) or better for ASF
or \(0.69^2\) (= 0.47 or 0.48) or better for ASF
M1ft: Dep on previous M1
A1: Awrt 583