Higher January 2020 Paper 2 Q4
4 The diagram shows a triangle.
Diagram NOT accurately drawn
Work out the value of \(x\).
(4)
| Scheme | Marks |
|---|---|
| 30 + \(4x\) + 10 + \(x\) + 20 (= \(5x\) + 60) or 180 – 30 (= 150) | M1 |
| e.g. 30 + \(4x\) + 10 + \(x\) + 20 = 180 or \(5x\) + 60 = 180 oe or 180 – 30 – 10 – 20 (= 120) | M1 |
| \(5x\) = ‘120’ or ‘120’ ÷ 5 | M1 |
| 24 | A1 |
| (4) | |
| (4 marks) |
Notes
M1: Allow \(5x + 60 = n\) where \(n \neq 180\) or for subtracting 30 from 180
OR M2 (for the first two M1 marks) for \(5x + 30 = 150\) oe
M1: for setting up the equation or for subtracting all numerical values of angles from 180
M1: for correctly simplifying to \(ax = b\) or for dividing ‘120’ by 5
A1: for 24