Higher November 2020 Paper 1R Q15
15

Diagram NOT accurately drawn
\(B\), \(D\), \(E\) and \(F\) are points on a circle.
\(ABC\) is the tangent to the circle at \(B\).
Angle \(EDF = 40^\circ\)
Angle \(FBC = 70^\circ\)
Prove that the tangent \(ABC\) is parallel to \(EF\).
Give a reason for each stage of your working.
(4)
| Scheme | Marks |
|---|---|
| \(BDF = 70^\circ\) | B1 |
| Alternate segment theorem | B1 |
| \(EFB\) = 180 – (70 + 40) = 70 opposite angles in a cyclic quadrilateral | B1 |
| \(CBF = EFB\) alternate angles therefore \(EF\) is parallel to \(ABC\) | B1 |
| (4) | |
| (4 marks) |
Notes
B1: may be marked on diagram
B1: reason, the angle between a tangent and a chord is equal to the angle subtended in the alternate segment
B1: Angle \(EFB\) with reason, opposite angles in a cyclic quadrilateral sum to 180°
B1: conclusion, alternate angles are equal