\(\text{‘}\dfrac{2}{5}\text{’} \times \text{‘}\dfrac{4}{5}\text{’}\left(= \dfrac{8}{25}\right)\) or \(\text{‘}\dfrac{2}{5}\text{’} \times \text{‘}\dfrac{1}{5}\text{’}\left(= \dfrac{2}{25}\right)\) or
\(\text{‘}\dfrac{3}{5}\text{’} \times \text{‘}\dfrac{4}{5}\text{’}\left(= \dfrac{12}{25}\right)\) or \(\text{‘}\dfrac{3}{5}\text{’} \times \text{‘}\dfrac{1}{5}\text{’}\left(= \dfrac{3}{25}\right)\) oe
M1
\(1 - \text{‘}\dfrac{8}{25}\text{’}\) or \(\text{‘}\dfrac{2}{25}\text{’} + \text{‘}\dfrac{12}{25}\text{’} + \text{‘}\dfrac{3}{25}\text{’}\) or \(\text{‘}\dfrac{2}{25}\text{’} + \text{‘}\dfrac{3}{5}\text{’}\) oe
M1
Correct answer scores full marks (unless from obvious incorrect working)
Answer: \(\dfrac{17}{25}\)
A1
(3)
(5 marks)
Notes
M1: ft from (a) provided \(0 \lt\) probability \(\lt 1\)
