Higher June 2022 Paper 1R Q9
9 Solve the inequality \(3 - 4x \leqslant 11\)
(2)
| Scheme | Marks |
|---|---|
| \(-4x \leqslant 11 - 3\) or \(-4x \leqslant 8\) or \(-x \leqslant 2\) or \(3 - 11 \leqslant 4x\) or \(-8 \leqslant 4x\) | M1 |
| \(x \geqslant -2\) | A1 |
| (2) | |
| (2 marks) |
Notes
M1: allow equals sign or condone incorrect inequality sign for M1 only
A1: allow \(-2 \leqslant x\)
SCB1 for \(x\) and −2 with an incorrect sign between them or −2 as an answer