Foundation November 2024 Paper 2 Q23
23 The diagram shows two right-angled triangles, ABC and BDC, joined at BC.
Not to scale
Work out angle BCA.
You must show your working. [5]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| 60 [\(^\circ\)] with correct working | 5 | Correct working requires evidence of at least M2A1M1 | |
| M2 for \(\sqrt{12^2 + 5^2}\) oe or M1 for \(5^2 + 12^2\) oe A1 for [BC = ] 13 | Condone stating 5, 12, 13 or \(5^2 + 12^2 = 13^2\) for M2 After M1, [BC =] 13 implies M2A1 [BC =] 13 might be on the diagram Do not penalise if Pythagoras is not subsequently used in work leading to their answer. | ||
| M1 for \(\dfrac{\textit{their}\ 13}{26} = \cos\) […] oe | |||
| If 0 or 1 scored, instead award SC2 for final answer of 60 nfww If 0 scored, instead award SC1 for [BC =] 13 | Note that: \(5 \times 12 = 60\) is SC0 | ||