Foundation June 2025 Paper 2 Q17
17 Solve.
\(2x - 1 \leqslant 11\) [2]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(x \leqslant 6\) final answer | 2 | M1 for \(2x \leqslant 11 + 1\) or better or for \(x - \dfrac{1}{2} \leqslant \dfrac{11}{2}\) or better or for answer 6 with or without equals sign or wrong inequality symbol | For M1 allow any inequality or equals signs: e.g. M1 for \(2x > 11 + 1\). |