Foundation June 2025 Paper 1 Q26
26 There are 483 counters in a bag.
The counters are blue, red or yellow.
The ratio of blue counters to red counters is 1 : 5.
The ratio of red counters to yellow counters is 4 : 9.
Work out the number of red counters in the bag. [4]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| 140 | 4 | M3 for \(483 \div (4 + 20 + 45) \times 20\) oe accept \(483 \div (m + 20 + 45) \times 20\) or \(483 \div (4 + 20 + n) \times 20\) or M2 for \(483 \div (4 + 20 + 45)\) oe accept \(483 \div (m + 20 + 45)\) or \(483 \div (4 + 20 + n)\) or M1 for 4 : 20 or 20 : 45 or 69 | Accept consistent equivalent ratios of the form \(4k : 20k\) or \(20k : 45k\) where \(k\) is a positive integer Ignore additional third part of the ratio |