Foundation January 2019 Paper 2 Q24

EdexcelFoundationCurrent spec3 marksLinear Graphs & Gradients

24 The line L is drawn on the grid.

Coordinate grid with x from −4 to 4 and y from −4 to 6 showing a straight line L through (0, 1) and (2, 4)

Find an equation for L.

(3)

Mark scheme

Scheme	Marks
3 ÷ 2 (= 1.5) or eg \(\dfrac{4 - 1}{2 - 0}\) or \(c = 1\)	M1
\(y = \text{``}{1.5}\text{''}x + c\) or \(y = mx + 1\) or eg \(y - 4 = m(x - 2)\)	M1
\(y = 1.5x + 1\) oe	A1
	(3)
	(3 marks)

Notes

M1: for correct method to find gradient or the correct value of \(c\).
For gradient, may see a correct calculation, 3/2 with evidence on diagram oe or \(1.5x\ (+ c)\)
For value of \(c\), allow \(c = 1\), \(y = 1\), (\(L =\)) \(mx + 1\) oe

M1: for use of \(y = mx + c\) with either \(m\) or \(c\)
or for (\(L =\)) \(1.5x + 1\) (NB: \(m \ne 0\))

A1: oe eg \(y - 4 = \dfrac{3}{2}(x - 2)\)

Note: the printed scheme shows the gradient calculation as \(\dfrac{4 - 1}{2(-0)}\); this is a misprint for \(\dfrac{4 - 1}{2 - 0}\), shown corrected above.