Foundation January 2019 Paper 1 Q20

EdexcelFoundationCurrent spec3 marksSimilar Shapes

Lines AD and BE cross at C. AB = 8 cm is parallel to ED = 20 cm, AC = 4.8 cm and BC = 6.4 cm

Diagram NOT accurately drawn

\(AB\) is parallel to \(ED\).
\(ACD\) and \(BCE\) are straight lines.

\(AB = 8\) cm
\(AC = 4.8\) cm
\(BC = 6.4\) cm
\(ED = 20\) cm

Work out the length of \(BE\).

(3)

Mark scheme

Scheme	Marks
\(\dfrac{20}{8}\) oe or 2.5 oe or \(\dfrac{8}{20}\) oe or 0.4 oe	M1
Eg \(6.4 \times \dfrac{20}{8} + 6.4\) or \(BE = 6.4 \div \dfrac{8}{20} + 6.4\)	M1
22.4	A1
	(3)
	(3 marks)

Notes

M1: for a correct scale factor

M1: for a complete method to find \(BE\)

Note: the printed scheme labels the second method “\(CE = 6.4 \div \dfrac{8}{20} + 6.4\)”; this expression gives \(BE\) (= \(CE + BC\)), so it is shown here as \(BE\).