Foundation June 2019 Paper 2 Q12

EdexcelFoundationCurrent spec3 marksLinear Graphs & Gradients

12 On the grid, draw the graph of \(y = 3x - 1\) for values of \(x\) from \(-2\) to 3

Coordinate grid with x from −2 to 4 and y from −8 to 11

(3)

Mark scheme

Scheme

Marks

x	−2	−1	0	1	2	3
y	−7	−4	−1	2	5	8

(−2, −7) (−1, −4) (0, −1)
(1, 2) (2, 5) (3, 8)
Answer: Correct line between \(x = -2\) and \(x = 3\)

(3)

(3 marks)

Notes

B3: for a correct line between \(x = -2\) and \(x = 3\)

(B2 for a correct straight line segment through at least 3 of (−2, −7) (−1, −4) (0, −1) (1, 2) (2, 5) (3, 8) or for all of (−2, −7) (−1, −4) (0, −1) (1, 2) (2, 5) (3, 8) plotted but not joined)

(B1 for at least 2 correct points stated (may be in a table) or plotted or for a line drawn with a positive gradient through (0, −1) or for a line with a gradient of 3)