Higher June 2023 Paper 2 Q9
9 Change a speed of 27 kilometres per hour to a speed in metres per second.
(3)
| Scheme | Marks |
|---|---|
For 27 × 1000 (= 27 000) or \(\dfrac{27}{60 \times 60}\left(= 0.0075 \text{ or } \dfrac{3}{400}\right)\) or \(\dfrac{1000}{60 \times 60}\left(\dfrac{5}{18} = 0.27(7...)\right)\) or sight of 450 | M1 |
\(\dfrac{27 \times 1000}{60 \times 60}\) oe eg (0.45 × 1000) ÷ 60 or 0.27…. × 27 | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: 7.5 | A1 |
| (3) | |
| (3 marks) |
Notes
M1: For one of ×1000 (eg sight of 27 000)
or
(÷60 ÷60) or ÷3600 oe
ie correct conversion of distance units or of time units
or
\(\dfrac{1000}{60 \times 60}\)
M1: For a fully correct method with correct use of brackets
eg 27 000 ÷ 60 × 60 is M1 only if not recovered
A1: oe eg \(\dfrac{15}{2}\) or \(7\dfrac{1}{2}\) oe
M2 for 27 ÷ 3.6 or \(27 \times \dfrac{5}{18}\)