Foundation June 2022 Paper 1R Q12

EdexcelFoundationCurrent spec3 marksAngles (Including Parallel Lines)

12 The diagram below shows the trapezium \(PQRS\)

Trapezium PQRS with right angles at P and Q; angle PSR is (3x − 24)° and angle QRS is (102 − x)°

Diagram NOT accurately drawn

Angle \(PQR\) and angle \(QPS\) are right angles.

Find the value of \(x\)

(3)

Mark scheme

Scheme	Marks
eg \(3x - 24 + 102 - x = 180\) oe or \(90 + 90 + 3x - 24 + 102 - x = 360\) oe	M1
eg \(2x = 180 - 78\) oe or \(2x = 360 - 258\) oe or eg (180 + 24 – 102) ÷ 2 or (360 – (90 + 90 – 24 + 102)) ÷ 2	M1
51	A1
	(3)
	(3 marks)

Notes

M1: for setting up a correct equation

M1: for simplifying and isolating the \(x\) term or for a complete calculation to find the value of \(x\)
(corrected from the printed mark scheme, which omits the outer brackets: 360 – (90 + 90 – 24 + 102) ÷ 2)