Foundation June 2024 Paper 2R Q23
23
\(\dfrac{3^{-2} \times 3^5}{3^{10}} = 3^n\)
Find the value of \(n\)
(2)
| Scheme | Marks |
|---|---|
eg \(3^3\) or \((3^{-2})\times3^{-5}\) or \(\dfrac{3^3}{(3^{10})}\) or \(\dfrac{(3^5)}{3^{12}}\) or \(\dfrac{(3^{-2})}{3^5}\) or \(3^{-12}(\times3^5)\) oe or \(-2 + 5 - 10\) oe or \(-12 + 5\) oe or \(3 - 10\) oe | M1 |
| Working not required, so correct answer scores full marks (unless from obvious incorrect working) Answer: −7 | A1 |
| (2) | |
| (2 marks) |
Notes
M1: for a correct application of an index rule as a first step or a correct calculation for n
A1: Allow \(3^{-7}\)