Foundation June 2024 Paper 2R Q7
7 Here are the first five terms of a number sequence.
−3 5 13 21 29
(a)
(i) Write down the next term of the sequence. (1)
(ii) Explain how you worked out your answer. (1)
(b) Explain why 326 cannot be a term of the sequence. (1)
| Scheme | Marks |
|---|---|
| (i) Answer: 37 | B1 |
| (ii) Answer: Added 8 | B1 |
| (2) |
Notes
B1: eg ‘added 8’, ‘add 8’, +8, rule is \(8n - 11\), goes up by 8, \(8 \times 6 - 11\) (= 37)
| Scheme | Marks |
|---|---|
| Acceptable answers 1. (the) sequence is odd 2. (326) is even or not odd 3. ‘nth term is \(8n - 11\) which will always be odd’ 4. ‘sequence goes 325, 333’ 5. (the) 42nd term is 325 6. should be 325 (not 326) 7. it would be 333 (not 326) 8. \(8n - 11\) so \(n\) is not an integer/whole number 9. \(337 \div 8\) oe (= 42.125) not an integer/whole number 10. not 11 less than a multiple of 8 11. does not end with 1, 3, 5, 7 and 9 (must have all 5 numbers) 12. each digit has an odd digit at the end/does not end in an odd number Not acceptable answers 1. adding 8 each time will not lead to 326 2. it goes past 326 3. \(326 \div 8\) (= 40.75) not an integer/whole number 4. 326 cannot be divided by 8 Answer: Correct explanation | B1 |
| (1) | |
| (3 marks) |