Foundation June 2024 Paper 1R Q24
24 Line L is drawn on the grid.
Find an equation for L
Give your answer in the form \(y = mx + c\)
(3)
| Scheme | Marks |
|---|---|
| \(y = -\dfrac{1}{2}x + 1\) | B3 |
| (3) | |
| (3 marks) |
Notes
B3: for \(y = -\dfrac{1}{2}x + 1\) oe but must be in form \(y = mx + c\)
eg \(y = -0.5x + 1\)
(B2 for (\(L\) =) \(-\dfrac{1}{2}x + 1\)
or for \(y = -\dfrac{1}{2}x + c\)
or for \(y = mx + 1\) where \(m \neq 0\)
or for a correct equation in the incorrect form eg \(2y + x = 2\))
(B1 for (\(L\) =) \(-\dfrac{1}{2}x + c\)
or (\(L\) =) \(mx + 1\) where \(m \neq 0\)
or \(m = -\dfrac{1}{2}\) or gradient = \(-\dfrac{1}{2}\) oe eg \(\dfrac{3 - (-1)}{-4 - 4}\))