Foundation June 2024 Paper 1R Q12
12

Diagram NOT accurately drawn
\(ABCD\) is a quadrilateral.
\(CDE\) is an isosceles triangle with \(CD = CE\)
\(DEF\) is a straight line.
Work out the size of angle \(BCE\)
Give a reason for each stage of your working.
(5)
| Scheme | Marks |
|---|---|
| \(CED = 180 - 125\ (= 55)\) or \(BCD = 360 - (86 + 78 + 128)\ (= 68)\) | M1 |
| \(DCE = 180 - (2 \times \text{``}{55}\text{''})\ (= 70)\) | M1 |
| Correct answer of 138 scores 3 marks (unless from obvious incorrect working) Answer: 138 | A1 |
| B2 | |
| (5) | |
| (5 marks) |
Notes
M1: angles may be marked on diagram or labelled unambiguously in working
M1: angles may be marked on diagram or labelled unambiguously in working
A1: for 138
B2: (dep on M2) for all correct reasons for their method
(B1 (dep on M1) for one correct reason for their method)
Angles on a straight line add to 180
Angles on a straight line add to 180
Isosceles triangle
Angles in a triangle add to 180
Angles in a triangle add to 180
Angles in a quadrilateral add to 360
Angles in a quadrilateral add to 360