Foundation June 2024 Paper 1 Q15
15 The diagram shows a shape \(ABCDE\) made from a right-angled triangle \(ABE\) and a square \(BCDE\)
Diagram NOT accurately drawn
\(ABC\) is a straight line.
\(AB = 15\) cm \(\qquad AE = 17\) cm
The perimeter of triangle \(ABE\) is 40 cm
Work out the area of the shape \(ABCDE\)
(4)
| Scheme | Marks |
|---|---|
40 – (17 + 15) (= 8) or \(\sqrt{17^2 - 15^2}\left(= \sqrt{289 - 225} = \sqrt{64} = 8\right)\) | M1 |
| “8” × “8” (= 64) | M1 |
| \(\dfrac{15 \times \text{``}{8}\text{''}}{2}\) (= 60) oe or | M1 |
| Working not required, so correct answer scores full marks (unless from obvious incorrect working) Answer: 124 | A1 |
| (4) | |
| (4 marks) |
Notes
M1: may be seen on diagram
M1: for area of square (can be seen on diagram)
M1: for area of triangle (can be seen on diagram)
M2 for use of formula for area of trapezium
\(\dfrac{1}{2} \times (15 + \text{``}{8}\text{''} + \text{``}{8}\text{''}) \times \text{``}{8}\text{''}\)