Foundation June 2023 Paper 2R Q20
20 A field is in the shape of a trapezium.
Diagram NOT accurately drawn
The field is sold for a price of $49 650
Given that 1 hectare = 10 000 m2
work out the average price of the field per hectare.
(4)
| Scheme | Marks |
|---|---|
\(\dfrac{1}{2}(330 + 170) \times 240\) (= 60 000) oe or \(\left(\dfrac{80 \times 240}{2}\right) + (170 \times 240) + \left(\dfrac{80 \times 240}{2}\right)\) (= 60 000) oe or (2 × 9600) + 40 800 (= 60 000) oe | M1 |
| [60 000] ÷ 10 000 (= 6) or 10 000 × 6 (= 60 000) | M1 |
| 49 650 ÷ [6] | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: 8275 | A1 |
| (4) | |
| (4 marks) |
Notes
M1: for working out the area of the trapezium
M1: ft their area (must come from a two dimensional area)
Allow \(\dfrac{\text{their area}}{10\,000}\)
M1: dep on either previous M1 ft their number of hectares
Allow \(\dfrac{49\,650}{\text{their number of hectares}}\)