Foundation June 2023 Paper 1R Q13
13 The diagram shows the plan of a garden.
Diagram NOT accurately drawn
Martyn covers the garden with square tiles of side length 50 cm.
There are no gaps between the tiles.
It takes 4 minutes to lay each tile.
Work out how long it takes Martyn to cover the whole garden with tiles.
Give your answer in hours and minutes.
(5)
| Scheme | Marks |
|---|---|
| eg 7.5 × 5 (= 37.5) oe or 8 × (10 – 7.5) (= 20) oe or 10 × 5 (= 50) oe or (10 – 7.5) × (8 – 5) (= 7.5) oe or 10 × 8 (= 80) oe or 7.5 × (8 – 5) (= 22.5) oe or eg 8 ÷ 0.5 (= 16) or (10 – 7.5) ÷ 0.5 (= 5) or (8 – 5) ÷ 0.5 (= 6) or 10 ÷ 0.5 (= 20) or 5 ÷ 0.5 (= 10) or 7.5 ÷ 0.5 (= 15) | M1 |
| eg “37.5” + “20” (= 57.5) oe or “50” + “7.5” (= 57.5) oe or “80” – “22.5” (= 57.5) oe or eg “16” × “5” (= 80) or “10” × “15” (= 150) or “5” × “6” (= 30) or “10” × “20” (= 200) | M1 |
| “57.5” ÷ \(0.5^2\) (= 230) oe or “575 000” ÷ 10 000 ÷ \(0.5^2\) oe or “57.5” ÷ “0.25” (= 230) oe or “57.5” ÷ (“2500” ÷ 10 000) (= 230) oe or eg “80” + “150” (= 230) or “30” + “200” (= 230) | M1 |
| “230” × 4 (= 920) | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: 15 hours 20 minutes | A1 |
| (5) | |
| (5 marks) |
Notes
M1: for a method to find a relevant area
OR
a method to find the number of tiles along one ‘row’
M1: for a method to find the total area of the shape
OR
a method to find the number of tiles needed for one rectangle
M1: dep on M1 for a method to find the total number of tiles required
(consistent units)
M1: dep on previous M1 for multiplying the total number of tiles by 4
A1: SCB1 for 0.5 × 0.5 (= 0.25) if no other marks are awarded
| Scheme | Marks |
|---|---|
| eg 750 × 500 (= 375 000) oe or 800 × (1000 – 750) (= 200 000) oe or 1000 × 500 (= 500 000) oe or (1000 – 750) × (800 – 500) (= 75 000) oe or 1000 × 800 (= 800 000) oe or 750 × (800 – 500) (= 225 000) oe or eg 800 ÷ 50 (= 16) or (1000 – 750) ÷ 50 (= 5) or (800 – 500) ÷ 50 (= 6) or 1000 ÷ 50 (= 20) or 500 ÷ 50 (= 10) or 750 ÷ 50 (= 15) | M1 |
| eg “375 000” + “200 000” (= 575 000) oe or “500 000” + “75 000” (= 575 000) oe or “800 000” – “225 000” (=575 000) oe or eg “16” × “5” (= 80) or “10” × “15” (= 150) or “5” × “6” (= 30) or “10” × “20” (= 200) | M1 |
| “575 000” ÷ \(50^2\) (= 230) oe or “57.5” × 10 000 ÷ \(50^2\) oe or “575 000” ÷ “2500” (= 230) or oe “575 000” ÷ (“0.25” × 10 000) (= 230) oe or eg “80” + “150” (= 230) or “30” + “200” (= 230) | M1 |
| “230” × 4 (= 920) | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: 15 hours 20 minutes | A1 |
Notes
M1: for a method to find a relevant area
OR
a method to find the number of tiles along one ‘row’
M1: for a method to find the total area of the shape
OR
a method to find the number of tiles needed for one rectangle
M1: dep on M1 for a method to find the total number of tiles required
(consistent units)
M1: dep on previous M1 for multiplying the total number of tiles by 4
A1: SCB1 for 50 × 50 (= 2500) if no other marks are awarded