Foundation June 2023 Paper 1R Q7
7
(a) Simplify \(6a \times 2c\) (1)
(b) Simplify \(4d + 3e + d - 5e\) (2)
(c) Solve \(4x - 7 = 23\) (2)
| Scheme | Marks |
|---|---|
| \(12ac\) | B1 |
| (1) |
| Scheme | Marks |
|---|---|
| \(5d - 2e\) | B2 |
| (2) |
Notes
B2: for \(5d - 2e\) oe
(B1 for \(5d\) or \(-2e\))
| Scheme | Marks |
|---|---|
\(4x = 23 + 7\) or \(4x = 30\) oe or \(x - \dfrac{7}{4} = \dfrac{23}{4}\) or (23 + 7) ÷ 4 or 30 ÷ 4 | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: 7.5 | A1 |
| (2) | |
| (5 marks) |
Notes
M1: for a correct first step
or a correct calculation for \(x\)
A1: oe eg \(\dfrac{15}{2}\), \(7\dfrac{1}{2}\), \(\dfrac{30}{4}\)