Foundation June 2018 Paper 1R Q16
16 Here is a hexagon \(ABCDEF\).
Diagram NOT accurately drawn
\(CD\) is parallel to \(AF\).
Work out the area of hexagon \(ABCDEF\).
(4)
| Scheme | Marks |
|---|---|
| 20 × 14 (= 280) | M1 |
| \(\dfrac{20 + 16}{2} \times (24 - 14)\) (= 180) | M1 |
| “280” + “180” | M1 |
| 460 | A1 |
| (4) | |
| (4 marks) |
Notes
M1: (dep) on at least one of the previous M marks
| Scheme | Marks |
|---|---|
| (24 + 14) ÷ 2 (= 19) and (20 − 16) ÷ 2 (= 2) | M1 |
| 2 × 19 (= 38) and 16 × 24 (= 384) | M1 |
| “38” + “38” + “384” | M1 |
| 460 | A1 |
Notes
M1: (dep) on at least one of the previous M marks
| Scheme | Marks |
|---|---|
| 20 × 24 (= 480) | M1 |
| (20 − 16) ÷ 2 (= 2) and 24 − 14 (= 10) 2 × 10 = 20 | M1 |
| “480” – “20” | M1 |
| 460 | A1 |
Notes
M1: (dep) on at least one of the previous M marks