Foundation January 2020 Paper 2R Q17
17 Three tins, \(A\), \(B\) and \(C\), each contain buttons.
Tin \(A\) contains \(x\) buttons.
Tin \(B\) contains 4 times the number of buttons that tin \(A\) contains.
Tin \(C\) contains 7 fewer buttons than tin \(A\).
The total number of buttons in the three tins is 137
Work out the number of buttons in tin \(C\).
(4)
| Scheme | Marks |
|---|---|
| \(4x\) or \(x - 7\) | M1 |
| \(x + 4x + x - 7 = 137\) oe | M1 |
| \(x = 144 \div 6\ (= 24)\) or \(6x = 144\) | M1 |
| 17 | A1 |
| (4) | |
| (4 marks) |
Notes
M1: Correct expression for \(B\) or \(C\)
M1: Correct equation
M1: Gathering up the \(x\)’s and numbers
Dep on previous M1