Foundation November 2024 Paper 2 Q14
14 The diagram shows a shape \(ABCDE\) made from a square \(ABDE\) and an isosceles triangle \(BCD\)
Diagram NOT accurately drawn
\(BC = DC\)
The area of square \(ABDE\) is 49 cm2
The perimeter of triangle \(BCD\) is 27 cm
Work out the perimeter of \(ABCDE\)
(3)
| Scheme | Marks |
|---|---|
(side of square =) \(\sqrt{49}\;(= 7)\) 7 could also be seen as part of a calculation eg 7 + 7 + 7….. | M1 |
| Other side of triangle = (27 – “7”) ÷ 2 (= 10) or 2 sides of triangle = 27 – “7” (= 20) 10 or 20 could also be seen as part of a calculation eg 7 + 7 +…+ 10 + 10 or 7 + 7 + …+ 20 | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: 41 | A1 |
| (3) | |
| (3 marks) |
Notes
M1: could be on the diagram
M1: dep on M1
but we will allow
use of their side of square when assuming 49 is the perimeter
eg \(\dfrac{27 - 12.25}{2}\;(= 7.375)\) or
27 – 12.25 (= 14.75)