Foundation June 2025 Paper 2 Q22
22 The diagram shows two similar quadrilaterals, \(ABCD\) and \(EFGH\)
Diagram NOT accurately drawn
\(AB = 5\) cm \(BC = 4\) cm \(CD = y\) cm
\(EF = x\) cm \(FG = 10\) cm \(GH = 24\) cm
(a) Work out the value of \(x\) (2)
(b) Work out the value of \(y\) (2)
| Scheme | Marks |
|---|---|
\(\dfrac{10}{4}\left(= \dfrac{5}{2} = 2.5\right)\) or \(\dfrac{4}{10}\left(= \dfrac{2}{5} = 0.4\right)\) or \(\dfrac{x}{5} = \dfrac{10}{4}\) oe or \(\dfrac{x}{10} = \dfrac{5}{4}\) oe | M1 |
| Working not required, so correct answer scores full marks (unless from obvious incorrect working) Answer: 12.5 | A1 |
| (2) |
Notes
M1: for a correct SF can be expressed as a fraction, decimal or ratio (may or may not be used)
or
for a correct equation in \(x\)
Allow any letter for \(x\)
A1: oe eg \(\dfrac{50}{4}\) or \(\dfrac{25}{2}\) or \(12\dfrac{1}{2}\) or \(12\dfrac{2}{4}\)
| Scheme | Marks |
|---|---|
24 ÷ [2.5] oe or \(\dfrac{y}{24} = \dfrac{4}{10}\) oe or \(\dfrac{y}{24} = \dfrac{5}{[12.5]}\) oe or \(\dfrac{y}{4} = \dfrac{24}{10}\) oe or \(\dfrac{y}{5} = \dfrac{24}{[12.5]}\) oe | M1 |
| Working not required, so correct answer scores full marks (unless from obvious incorrect working) Answer: 9.6 | A1 |
| (2) | |
| (4 marks) |
Notes
M1: ft ie [2.5] is their SF from (a)
or
for a correct equation in \(y\)
Allow any letter for \(y\)
ft their answer to (a) ie [12.5] is their answer to (a)
A1: oe eg \(\dfrac{48}{5}\) or \(9\dfrac{3}{5}\)
If (a) \(x = 9.6\) and (b) \(y = 12.5\) then M1A0M1A0