Foundation January 2021 Paper 2 Q11
11
Diagram NOT accurately drawn
\(ABD\) is a triangle.
\(AEDF\), \(BCDG\) and \(HCEJ\) are straight lines.
\(BA\) is parallel to \(HCEJ\).
Work out the size of the angle marked \(x\).
(3)
| Scheme | Marks |
|---|---|
| \(ABD\) = 180 – 143 (= 37) or \(AEJ\) = 76 or \(CED\) = 76 or \(ECD\) = 180 – 143 ( = 37) | M1 |
| 180 – 76 – “37” | M1 |
| 67 | A1 |
| (3) | |
| (3 marks) |
Notes
M1: may be marked on diagram
M1: A correct calculation for \(EDC\)