Higher November 2019 Paper 2 Q12
12 The diagram shows triangle \(ABC\).
\(ADC\) and \(DEB\) are straight lines.
\(AD = 4.4\) cm
\(BC = 8.6\) cm
\(E\) is the midpoint of \(DB\).
Angle \(CDB = 90^\circ\)
Angle \(DCB = 40^\circ\)
Work out the size of angle \(EAD\).
Give your answer correct to 1 decimal place.
You must show all your working. (4)
| Answer | Mark | Mark scheme |
|---|---|---|
| 32.1 | P1 | starts process, eg \(\sin 40 = \dfrac{DB}{8.6}\) oe or for \(8.6 \times \sin 40\ (= 5.52797\ldots)\) |
| P1 | complete process to find \(ED\), eg \((8.6 \times \sin 40) \div 2\ (= 2.76\ldots)\) | |
| P1 | process to find angle \(EAD\), eg \(\tan^{-1}\left(\dfrac{\text{``}2.76\ldots\text{''}}{4.4}\right)\) or \(\tan^{-1}(\text{``}0.628\ldots\text{''})\) | |
| A1 | answer in range 32.09 to 32.2 |
Additional guidance
Accept values rounded or truncated to 2 dp.
If an answer in the range is seen in working and then incorrectly rounded award full marks