Higher June 2017 Paper 1 Q21
21 \(ABCD\) is a quadrilateral.

\(AB = CD\).
Angle \(ABC\) = angle \(BCD\).
Prove that \(AC = BD\). (4)
| Answer | Mark | Notes |
|---|---|---|
| C1 | states (angle) \(ABC\) = (angle) \(BCD\) | |
| C1 | states 2nd link \(AB = CD\) | |
| C1 | states 3rd link with reason: \(BC = BC\) (common) | |
| C1 | concludes proof by stating (triangle) \(ABC \equiv\) (triangle) \(DCB\) with reason SAS and \(AC = BD\) |