Higher November 2017 Paper 2 Q7
7 \(ABCD\) is a trapezium.
Work out the size of angle \(CDA\).
Give your answer correct to 1 decimal place. (5)
| Answer | Mark | Notes |
|---|---|---|
| 32.3 | P1 | for using Pythagoras to find length of third side of triangle, eg \(7.5^2 - 6^2\) or \(6^2 + x^2 = 7.5^2\) or uses trigonometry to find angle in triangle eg \(\sin A = \dfrac{6}{7.5}\) or \(\cos B = \dfrac{6}{7.5}\) |
| P1 | (dep P1) for complete process to find length of third side of triangle eg \(\sqrt{7.5^2 - 6^2}\) or \(\sqrt{56.25 - 36}\) or \(\sqrt{20.25}\ (= 4.5)\) or uses trigonometry to find base length of triangle eg \(7.5 \times \cos \text{``}A\text{''}\) or \(7.5 \times \sin \text{``}B\text{''}\) or \(\dfrac{6}{\tan \text{``}A\text{''}}\) | |
| P1 | (dep P2) for \(24 - 10 - \text{``}4.5\text{''}\ (= 9.5)\) | |
| P1 | (indep) for process to find angle \(CDA\), eg \(\tan CDA = \dfrac{6}{\textit{base}}\) from right-angled triangle | |
| A1 | for answer in the range 32.2 to 32.3 |