Higher November 2023 Paper 2 Q13
13 Prove algebraically that \(0.0\dot{7}2\dot{3}\) can be written as \(\dfrac{241}{3330}\) (3)
| Answer | Mark | Mark scheme |
|---|---|---|
| Proof | M1 | for eg, \((10x =)\ 0.723723\ldots\) or \((100x =)\ 7.237237\ldots\) or \((1000x =)\ 72.372372\ldots\) or \((10000x =)\ 723.723723\ldots\) |
| M1 | (dep M1) for a method using two recurring decimals that leads to a terminating decimal difference, using correct multiples of \(x\) eg \((10000x - 10x =)\ 723.723723\ldots - 0.723723\ldots\) | |
| A1 | for completing the algebra to \(\dfrac{241}{3330}\) oe |
Additional guidance
Any recurring notation acceptable throughout.
Proofs with terminating decimals (less than 6 figures) score M1M1A0