Higher November 2023 Paper 1 Q12
12 The straight line L has equation \(2y = 3x - 7\)
Find an equation of the straight line perpendicular to L that passes through \((6, -5)\) (3)
| Answer | Mark | Mark scheme |
|---|---|---|
| \(y = -\dfrac{2}{3}x - 1\) | M1 | for a method to find gradient of perpendicular line, eg \(y = \dfrac{3}{2}x\left(-\dfrac{7}{2}\right)\) and \(\dfrac{3}{2} \times m = -1\) or gradient of perpendicular shown as \(-\dfrac{2}{3}\) |
| M1 | for a method to find the value of \(c\), eg \(-5 = \text{``}{-\dfrac{2}{3}}\text{''} \times 6 + c\) or \(y - {-5} = \text{``}{-\dfrac{2}{3}}\text{''}(x - 6)\) oe | |
| A1 | for \(y = -\dfrac{2}{3}x - 1\) oe eg \(2x + 3y + 3 = 0\) or \(y + 5 = -\dfrac{2}{3}(x - 6)\) SC B1 for \(y = -\dfrac{1}{3}x - 3\) oe if M0 scored |