Higher November 2022 Paper 1 Q2
2
(a) Work out \(1\dfrac{3}{5} + 2\dfrac{1}{4}\)
Give your answer as a mixed number. (2)
Give your answer as a mixed number. (2)
(b) Show that \(2\dfrac{2}{3} \div 6 = \dfrac{4}{9}\) (2)
| Answer | Mark | Mark scheme |
|---|---|---|
| \(3\dfrac{17}{20}\) | M1 | for finding two fractions with a correct common denominator (multiple of 20), with at least one correct corresponding numerator, eg \(\dfrac{12}{20}\), \(\dfrac{5}{20}\) or \(\dfrac{32}{20}\), \(\dfrac{45}{20}\) |
| A1 | for \(3\dfrac{17}{20}\) or an equivalent mixed number SC B1 for an answer of 3.85 if M0 scored |
Additional guidance
May be from \(\dfrac{3}{5}\) and \(\dfrac{1}{4}\) or from \(\dfrac{8}{5}\) and \(\dfrac{9}{4}\)
| Answer | Mark | Mark scheme |
|---|---|---|
| shown | M1 | for \(\dfrac{8}{3} \times \dfrac{1}{6}\) oe or \(\dfrac{4}{9} \times \dfrac{6}{1}\) oe or \(\dfrac{8}{3} \times \dfrac{9}{4}\) oe |
| A1 | for unsimplified fraction which could lead to \(\dfrac{4}{9}\), eg \(\dfrac{8}{18}\) or for \(\dfrac{4}{3} \times \dfrac{1}{3}\) or \(\dfrac{24}{9} \div 6\) or for unsimplified fraction which could lead to \(2\dfrac{2}{3}\), eg \(\dfrac{24}{9}\) or for unsimplified fraction which could lead to 6, eg \(\dfrac{72}{12}\) |