Higher November 2018 Paper 2 Q24
24 Here is a sketch of \(\quad y = \text{f}(x)\)
The curve passes through the points
\(({-2}, {-10}) \quad ({-1}, {-3}) \quad (0, {-2}) \quad (1, {-1}) \quad (2, 6)\)
On the grid, sketch the curve \(\quad y = \text{f}(x + 2)\) [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| Plots at least three of \((0, 6) \quad ({-1}, {-1}) \quad ({-2}, {-2})\) \(({-3}, {-3}) \quad ({-4}, {-10})\) | M1 | points may be implied by a curve passing through the points tolerance ±2 mm |
| Plots \((0, 6) \quad ({-1}, {-1}) \quad ({-2}, {-2})\) \(({-3}, {-3}) \quad ({-4}, {-10})\) and joins with a smooth curve | A1 | points may be implied by a curve passing through the points tolerance ±2 mm |
Additional guidance
| Draws \(\quad y = \text{f}(x - 2)\) or \(y = \text{f}(x) + 2\) or \(y = \text{f}(x) - 2\) | M0A0 |