Higher June 2019 Paper 1 Q19
19 Circle the fraction that is equivalent to \(\quad 0.\dot{1}\) [1 mark]
- \(\dfrac{1}{9}\)
- \(\dfrac{1}{99}\)
- \(\dfrac{1}{10}\)
- \(\dfrac{11}{100}\)
| Answer | Mark | Comments |
|---|---|---|
| \(\dfrac{1}{9}\) | B1 |
19 Circle the fraction that is equivalent to \(\quad 0.\dot{1}\) [1 mark]
| Answer | Mark | Comments |
|---|---|---|
| \(\dfrac{1}{9}\) | B1 |