Higher November 2020 Paper 2 Q7

AQACurrent spec3 marksDrawing & Using Graphs

7 Here is the graph of \(\quad y = x^2 - 7x + 10 \quad\) for values of \(x\) from 0 to 7

Graph of y = x squared minus 7x plus 10 for x from 0 to 7. The curve crosses the y-axis at 10, crosses the x-axis at 2 and 5, and has its lowest point at about (3.5, −2.25)
(a) Write down the roots of \(\quad x^2 - 7x + 10 = 0\) [2 marks]
(b) Write down the \(x\)-coordinate of the turning point of the curve. [1 mark]