Higher November 2017 Paper 3 Q21
21 \(N\) is a number.
As a product of prime factors in index form \(\quad N = 2 \times 3^4 \times y^3\)
Work out \(\;3N^2\;\) as a product of prime factors in index form.
Give your answer in terms of \(y\). [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(3^8\) or \(3^9\) or \(y^6\) or \(2 \times 3^4 \times y^3 \times 2 \times 3^4 \times y^3\) or \(3 \times 2 \times 3^4 \times y^3 \times 2 \times 3^4 \times y^3\) | M1 | 78 732 or 19 683 |
| \(2^2 \times 3^8 \times y^6\) or \(3 \times 2^2 \times 3^8 \times y^6\) or \(2^2\) and \(3^9\) and \(y^6\) or \(2^a \times 3^b \times y^c\) with two powers correct | M1dep | \(2^2 \times 19\,683y^6\) \(78\,732y^6\) |
| \(2^2 \times 3^9 \times y^6\) | A1 | Must be in index form Do not ignore fw |
Additional guidance
| \(2^2 \times 3^8 \times y^6\) | M1 M1 A0 |
| \(2^2 + 3^9 \times y^6\) | M1 M1 A0 |
| \(2^2 + 3^8 + y^6\) | M1 M0 A0 |