Foundation June 2018 Paper 3 Q10
10 Here is a scale drawing.
The Ferris wheel has a height of 130 m
Work out the height of the building. [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| Alternative method 1 | ||
| 2 (cm) and 10 (cm) or (scale factor =) 5 | M1 | each \(\pm\) 0.2 cm oe implied by 650 in working |
| \(130 \times 5\) or \(130 \div\) their \(2 \times\) their 10 | M1dep | oe |
| 650 | A1ft | ft [1.8, 2.2] and [9.8, 10.2] SC2 [635, 665] |
| Alternative method 2 | ||
| 2 (cm) and \(130 \div\) their 2 or 65 | M1 | \(\pm\) 0.2 cm |
| 10 (cm) and their \(65 \times\) their 10 | M1dep | \(\pm\) 0.2 cm |
| 650 | A1ft | ft [1.8, 2.2] and [9.8, 10.2] SC2 [635, 665] |
Additional guidance
| Do not accept marked graduations on diagram as a scale factor | |
| Allow consistent use of mm throughout | |
| 2 and 9.9 followed by \(130 \div 2 \times 9.9\) with answer 643.5 or 644 | M1M1A1ft |
| \(130 \times 4 + 124 = 644\) | SC2 |
| 2.1 and 10.1 followed by \(130 \div 2.1 \times 10.1\) | M1M1 |
| \(130 \times 4\) (= 520) + 130 | M1M1 |
| (\(130 \times 5 =\)) 650 followed by \(650 - 130\) | M1M0 |
| (\(130 \times 5 =\)) 650 followed by \(130 \times 650 = 84\,500\) | M1M0 |
| 1:5 or 5:1 is oe (scale factor =) 5 | M1 |
| \(130 \times 4\) (= 520) | M0 |