Foundation June 2018 Paper 1 Q31
31 A large rectangle is made by joining three identical small rectangles as shown.

Not drawn accurately
The perimeter of one small rectangle is 15 cm
Work out the perimeter of the large rectangle. [4 marks]
| Answer | Mark | Comments |
|---|---|---|
| Alternative method 1 – width of small rectangle is \(x\) (any letter) | ||
| \(x\) and \(2x\) or \(x + 2x + x + 2x\) or \(6x\) | M1 | oe |
| \(x + 2x + x + 2x = 15\) or \(6x = 15\) | M1dep | oe |
| \((x =)\) 2.5 | A1 | from correct working or with 5 as the other dimension or with 7.5 as the length of the large rectangle |
| 25 | A1ft | ft \(10 \times\) their 2.5 with M1M1 awarded |
| Alternative method 2 – length of small rectangle is \(x\) (any letter) | ||
| \(x\) and \(\dfrac{x}{2}\) or \(x + \dfrac{x}{2} + x + \dfrac{x}{2}\) or \(3x\) | M1 | oe |
| \(x + \dfrac{x}{2} + x + \dfrac{x}{2} = 15\) or \(3x = 15\) | M1dep | oe |
| \((x =)\) 5 | A1 | from correct working or with 2.5 as the other dimension or with 7.5 as the length of the large rectangle |
| 25 | A1ft | ft \(5 \times\) their 5 with M1M1 awarded |
| Alternative method 3 – \(a\) = width of small rectangle and \(b\) = length of small rectangle (any letters) | ||
| \(b = 2a\) or \(10a\) or \(5b\) | M1 | correct expression for perimeter of the large rectangle in one variable |
| \(6a = 15\) or \(3b = 15\) | M1dep | correct equation in one variable |
| \((a =)\) 2.5 or \((b =)\) 5 | A1 | from correct working or with both values correct or with one value correct and 7.5 as the length of the large rectangle |
| 25 | A1ft | ft \(10 \times\) their \(a\) or \(5 \times\) their \(b\) with M1M1 awarded |
| Alternative method 4 – trial and improvement using ratio of sides | ||
| length \(= 2 \times\) width seen or implied | M1 | |
| Two correctly evaluated trials for perimeter of small rectangle with length \(= 2 \times\) width | M1dep | eg \(8 + 4 + 8 + 4 = 24\) and \(10 + 5 + 10 + 5 = 30\) |
| 2.5 and 5 | A1 | implied by \(2.5 + 5 + 2.5 + 5 = 15\) |
| 25 | A1 | |
Additional guidance
| Note that there is no ft in method 4 | |
| In all methods, marks can be awarded for annotation of the diagram, with lengths clearly identified, or working inside or alongside the diagram | |
| eg 2.5 and 5 marked correctly as the dimensions of the small rectangle | M1M1A1 |
| 2.5 marked as the width of the small rectangle and 7.5 marked as the length of the large rectangle | M1M1A1 |
| If full marks not awarded, mark both the diagram and working then award the better mark | |
| In alt 4, one or more trials may be crossed out to indicate that they do not give the correct perimeter. Do not treat this as the usual crossed out work not to be marked if replaced. |