Foundation June 2018 Paper 1 Q11
11 300 passengers go on a coach trip.
Each coach takes 50 passengers.
Each passenger pays £25
The table shows the costs for the coach company.
| Cost for each coach | |
|---|---|
| Pay for driver | £90 |
| Fuel | 70p per mile |
Each coach travels 200 miles.
Work out the total profit the company makes from this trip. [6 marks]
| Answer | Mark | Comments |
|---|---|---|
| Alternative method 1 – coaches, income, fuel, drivers, profit, answer | ||
| 6 | B1 | number of coaches |
| \(300 \times 25\) or 7500 or \(50 \times 25\) or 1250 | M1 | total income for one or all coaches |
| (their 6) \(\times 200 \times 0.7\) or 140 or 840 or (their 6) \(\times 200 \times 70\) or 14 000 or 84 000 | M1 | cost of fuel for one or all coaches 140 is implied by 230 (fuel \(+\) one driver) |
| their \(6 \times 90\) or 540 or their \(1250 -\) their \(140 - 90\) or 1020 | M1 | cost of all drivers or profit for one coach |
| their \(7500 -\) their \(840 -\) their 540 or their \(6 \times\) their 1020 | M1dep | oe method to calculate profit must be consistent units dependent on M3 |
| 6120 | A1 | |
| Alternative method 2 – profit per passenger | ||
| \(90 \div 50\) or 1.8(0) | B1 | cost per passenger for a driver |
| \(200 \times 0.7\) or 140 or \(200 \times 70\) or 14 000 | M1 | cost of fuel per coach |
| their \(140 \div 50\) or 2.8(0) or their \(14\,000 \div 50\) or 280 | M1dep | cost per passenger for the fuel dependent on M1 |
| \(25 -\) their \(1.8(0) -\) their 2.8(0) or 20.4(0) | M1dep | oe profit made per passenger must be consistent units dependent on B1M1M1 |
| their \(20.4(0) \times 300\) | M1dep | method to calculate total profit must be consistent units dependent on previous mark |
| 6120 | A1 | |
Additional guidance
| \(540 + 840\) or 1380 (without evidence for the second mark) | B1M0M1M1 (Alt 1) |
| 6 (for B1) may be implied by a calculation or value such as 540 | (Alt 1) |