Higher November 2021 Paper 1 Q10
10
(a) Work out \(\quad 2000 \times 70\,000\)
Give your answer in standard form. [2 marks]
(b) Work out \(\quad \dfrac{1.8 \times 10^2}{3 \times 10^{-1}}\)
Give your answer as an ordinary number. [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(2 \times 10^3\) or \(7 \times 10^4\) or 140 000 000 | M1 | oe correct value not in standard form eg \(14 \times 10^7\) |
| \(1.4 \times 10^8\) | A1 | SC1 Correctly converts an ordinary number with at least four digits to standard form |
Additional guidance
| Condone extra zeros on 1.4 eg \(1.40\,000\,000 \times 10^8\) | M1A1 |
| \(1.4 \times 10^8\) from 1 400 000 000 | M0A0 |
| \(2 \times 10^3\) is implied by \((2 \times 7) \times (10^3 \times 10^a)\) \(7 \times 10^4\) is implied by \((2 \times 7) \times (10^b \times 10^4)\) | M1 |
| 1 400 000 000 converted to \(1.4 \times 10^9\) | SC1 |
| Answer | Mark | Comments |
|---|---|---|
| 180 or 0.3 or (\(1.8 \div 3\) =) 0.6 or (\(10^2 \div 10^{-1}\) =) \(10^3\) or calculation which would have the outcome 600 or correct value not given as an ordinary number | M1 | eg \(1800 \div 3\) eg \(6 \times 10^2\) |
| 600 | A1 |
Additional guidance
| \(1800 \div 0.3 = 600\) scores M1 only, as 600 comes from incorrect working | M1A0 |
| \(1800 \div 30 = 600\) scores zero, as 600 comes from incorrect working | M0A0 |