Higher June 2022 Paper 2 Q27
27 To be rented, a bedroom must have a floor area of at least 6.51 m2
A bedroom has a rectangular floor.
The floor measures 2.4 m by 2.9 m, each correct to 2 significant figures.
Show that the bedroom can be rented. [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| Alternative method 1 | ||
| Sight of at least one of 2.35 or 2.45 or 2.85 or 2.95 | M1 | allow \(2.44\dot{9}\) for 2.45 and \(2.94\dot{9}\) for 2.95 |
| their \(2.35 \times\) their 2.85 | M1 | \(2.3 \leqslant\) their \(2.35 \lt 2.4\) \(2.8 \leqslant\) their \(2.85 \lt 2.9\) |
| \(2.35 \times 2.85\) selected and 6.6(975) | A1 | accept 6.7(0) or 6.698 with \(2.35 \times 2.85\) selected |
| Alternative method 2 | ||
| Sight of at least one of 2.35 or 2.45 or 2.85 or 2.95 | M1 | allow \(2.44\dot{9}\) for 2.45 and \(2.94\dot{9}\) for 2.95 |
| \(6.51 \div\) their 2.35 or \(6.51 \div\) their 2.85 | M1 | \(2.3 \leqslant\) their \(2.35 \lt 2.4\) \(2.8 \leqslant\) their \(2.85 \lt 2.9\) |
| \(6.51 \div 2.35\) and 2.7(7…) and 2.85 or \(6.51 \div 2.85\) and 2.2(8…) and 2.35 | A1 | |
Additional guidance
| Alt 1 \(2.35 \times 2.85\) amongst other calculations eg \(2.45 \times 2.95\) and/or \(2.35 \times 2.95\) can still score the second M1 but it must be clear that they are considering \(2.35 \times 2.85 = 6.6(975)\) to show that the bedroom can be rented | |
| eg1 \(2.35 \times 2.85 = 6.6975 \qquad 2.45 \times 2.95 = 7.2275\) | M1M1A0 |
| eg2 \(2.35 \times 2.85 = 6.6975 \qquad 2.45 \times 2.95 = 7.2275\) \(2.35 \times 2.95 = 6.9325 \qquad\) The lower bounds show it can be rented | M1M1A1 |
| Ignore the calculation \(2.4 \times 2.9\) throughout | |
| Alt 1 6.6(975) or 6.7 or 6.698 without \(2.35 \times 2.85\) selected | A0 |
| 6.6975 only | M0M0A0 |
| Alt 2 2.7(7…) without \(6.51 \div 2.35\) and 2.85 seen | A0 |
| Alt 2 2.2(8…) without \(6.51 \div 2.85\) and 2.35 seen | A0 |