Foundation November 2019 Paper 1 Q14
14 \(ABEF\) and \(ACDF\) are rectangles.
\(AF = 10\) cm \(AB = 2\) cm \(BC = 4\) cm
Not drawn accurately
Work out
perimeter \(ABEF\) : perimeter \(ACDF\)
Give your answer in its simplest form. [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| 10 + 2 + 10 + 2 or 24 or 10 + 6 + 10 + 6 or 32 | M1 | oe may be seen in a ratio |
| 10 + 2 + 10 + 2 or 24 and 10 + 6 + 10 + 6 or 32 | A1 | oe may be seen in a ratio |
| 3 : 4 | B1ft | ft correct and full simplification of any unsimplified ratio except answer 4 : 3 with M1A1 scored SC2 6 : 7 SC1 12 : 14 |
Additional guidance
| Ignore any units given | |
| Answer 3 : 4 with no incorrect working | M1A1B1 |
| \(1 : 1.\dot{3}\) | M1A1B0 |
| Working with half perimeter consistently 12 : 16 = 3 : 4 answer 12 : 16 or 6 : 8 | M1A1B1 M1A1B0 |
| 24 and 32 then 32 : 24 = 4 : 3 cannot be awarded B1ft as this would be full marks for an incorrect final answer | M1A1B0 |
| 32 : 24 | M1A1B0 |
| 24 : 42 = 4 : 7 | M1A0B1ft |
| 10 : 6 = 5 : 3 | M0A0B1ft |
| 20 : 12 = 10 : 6 (not fully simplified) | M0A0B0ft |
| 20 : 60 = 1 : 3 | M0A0B1ft |
| 14 : 22 = 6 : 10 = 3 : 5 (6 : 10 is an error, then simplifying this to 3 : 5 is not B1ft) | M0A0B0ft |