Foundation November 2020 Paper 3 Q27
27 Circle the expression that is equivalent to \(\quad (x - 1)^2\) [1 mark]
- \(x^2 - 1\)
- \(x^2 + 1\)
- \(x^2 - 2x - 1\)
- \(x^2 - 2x + 1\)
| Answer | Mark | Comments |
|---|---|---|
| \(x^2 - 2x + 1\) | B1 |
27 Circle the expression that is equivalent to \(\quad (x - 1)^2\) [1 mark]
| Answer | Mark | Comments |
|---|---|---|
| \(x^2 - 2x + 1\) | B1 |