Foundation November 2020 Paper 3 Q25
25 Chris visits a library.
He cycles to the library in half an hour at a speed of 12 miles per hour.
He stays at the library for one hour.
He then cycles home.
The sketch graph represents his visit.
Work out the speed, in miles per hour, at which Chris cycles home. [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| Alternative method 1 | ||
| \(12 \times \dfrac{30}{60}\) or \(12 \times \dfrac{1}{2}\) or 6 | M1 | oe eg \(12 \div 2\) |
| \(135 - 90\) or 45 | M1 | oe eg \(\dfrac{3}{4}\) |
| 8 | A1 | |
| Alternative method 2 | ||
| \(\dfrac{30}{135 - 90}\) or \(\dfrac{30}{45}\) or \(\dfrac{2}{3}\) or \(\dfrac{135 - 90}{30}\) or \(\dfrac{45}{30}\) or \(\dfrac{3}{2}\) | M1 | oe eg \(30 : (135 - 90)\) or 30 : 45 or 2 : 3 or \((135 - 90) : 30\) or 45 : 30 or 3 : 2 |
| \(12 \times \dfrac{30}{135 - 90}\) | M1dep | oe eg \(\dfrac{12 \times 30}{45}\) eg \(12 \div \dfrac{3}{2}\) |
| 8 | A1 | |
Additional guidance
| Award M1 or M2 work even if not subsequently used | |
| Check diagram for working | |
| 0.133… implies M1M1 | |
| \(12 \div 3 = 4\) and \(12 - 4 = 8\) | M2A1 |
| Answer \(-8\) | M2A0 |
| Ignore units unless 6 or 45 is from clearly incorrect working eg 12 (mph) = 60 minutes 6 (mph) = 30 minutes eg 12 (mph) = 30 minutes 6 (mph) = 15 minutes | M1 M0 |