Higher June 2023 Paper 2 Q20
20
(a) \(P\), \(Q\) and \(R\) are points on a circle.
\(S\) is a point inside triangle \(PQR\).

Not drawn accurately
Assume that \(S\) is the centre of the circle.
Work out the size of angle \(x\). [1 mark]
(b) In fact, the centre of the circle is on \(PS\) but not at \(S\).
What does this mean about the size of angle \(x\)?
Tick one box. [1 mark]
- It is the same as the answer to part (a)
- It is greater than the answer to part (a)
- It is smaller than the answer to part (a)
- It is impossible to tell
(c) For a different circle,
\(AB\) is a tangent at \(A\)
\(C\) and \(D\) are on the circumference of the circle
\(AC = CD\)

Not drawn accurately
Here is Simon’s method to work out the size of angle \(y\).
| Angle \(ADC = 70^\circ\) (alternate segment theorem) Therefore \(\quad y = 70^\circ\) (angles in an isosceles triangle) |
Is he correct?
Give a reason for your answer. [1 mark]
| Answer | Mark | Comments |
|---|---|---|
| 65 | B1 |
Additional guidance
| 65 unambiguously linked to \(x\) on diagram with answer line blank | B1 |
| Answer | Mark | Comments |
|---|---|---|
| It is greater than the answer to part (a) | B1 |
| Answer | Mark | Comments |
|---|---|---|
| No and valid statement | B1 | eg no it is angle \(ACD\) that is 70° |
Additional guidance
| Angles may be seen on the diagram | |
| No may be implied eg1 angle \(ADC\) is not 70 eg2 angle \(y\) is 55 | B1 B1 |
| Allow unambiguous indication of angles eg \(y\) and \(D\) are both 55 so he is wrong | B1 |
| No and angle \(ADC = 55^\circ\) | B1 |
| \(y\) is not 70 so no | B1 |
| No, neither angle is correct | B1 |
| No, he thinks \(AB\) and \(DC\) are parallel | B1 |
| No, he’s used alternate angles | B1 |
| It should say alternate angles (no implied) | B1 |
| He has made mistakes | B0 |
| He used the alternate segment theorem incorrectly | B1 |
| Ignore irrelevant working but do not ignore incorrect working eg No it is angle \(ACD\) that is 70° and angle \(y\) is 65 | B0 |
| Responses saying he is correct | B0 |