Foundation June 2019 Paper 2 Q28
28 A linear sequence starts
\[11 \qquad 21 \qquad 31 \qquad 41 \qquad \ldots\]Work out an expression for the \(n\)th term of the sequence. [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(10n + 1\) or \(1 + 10n\) | B2 | B1 \(10n\ (\ldots)\) |
Additional guidance
| Ignore LHS of formula given \(\quad\) eg \(\text{T}n = 10n + 1\) | B2 |
| Condone \(n = 10n + 1\) or \(n\)th term \(= 10n + 1\) | B2 |
| Allow other variables eg \(10x + 1\) | B2 |
| Allow a multiplication sign eg \(10 \times n + 1\) or \(n \times 10 + 1\) | B2 |
| \(n10 \ldots\) | B1 |
| \(n10 + 1\) | B1 |
| \(10n + 1n\) | B0 |
| Choice eg \(10n + 1\) and \(1n + 10\) | B0 |