Higher June 2024 Paper 1 Q1
1 Work out \(\quad 12^2 \div \left(\dfrac{1}{3} \times \sqrt{36}\right)\) [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| \((12^2 =)\ 144\) or \((\sqrt{36} =)\ 6\) or \(\left(\dfrac{1}{3} \times \sqrt{36} =\right) 2\) | M1 | implied by correct answer accept \((\sqrt{36} =)\ \pm 6\) or \(\left(\dfrac{1}{3} \times \sqrt{36} =\right) \pm 2\) |
| \((12^2 =)\ 144\) and \(\left(\dfrac{1}{3} \times \sqrt{36} =\right) 2\) | M1dep | implied by correct answer \(144 \times \dfrac{1}{2}\) or \(\dfrac{432}{6}\) oe fraction implies M1M1 accept \(\left(\dfrac{1}{3} \times \sqrt{36} =\right) \pm 2\) |
| 72 | A1 | accept \(\pm 72\) SC2 288 |
Additional guidance
| \(-72\) only | M1M1A0 |
| Condone missing brackets if recovered eg \(12^2 \div \dfrac{1}{3} \times 6\) with answer 72 | M1M1A1 |
| \(\dfrac{144}{\frac{1}{3} \times 6}\) with no further correct work | M1M0A0 |
| Using a decimal for \(\dfrac{1}{3}\) must be recovered |