Foundation November 2022 Paper 1 Q17
17 There are only blue counters, green counters, red counters and yellow counters in a bag.
The table shows the number of blue counters in the bag.
| Colour | blue | green | red | yellow |
|---|---|---|---|---|
| Number of counters | 30 |
There is a total of 100 counters in the bag.
Ashin takes at random a counter from the bag.
(a) Find the probability that the counter is not blue. (2)
The ratio of the number of blue counters to the number of green counters is 2 : 3
(b) Work out the number of green counters in the bag. (2)
Bradley says,
“The number of red counters in the bag is the same as the number of yellow counters in the bag.”
(c) Can Bradley be correct?
Give a reason for your answer. (1)
Give a reason for your answer. (1)
| Answer | Mark | Mark scheme |
|---|---|---|
| \(\dfrac{70}{100}\) | M1 | for \(100 - 30\ (= 70)\) or \(\dfrac{30}{100}\) oe |
| A1 | for \(\dfrac{70}{100}\) oe |
Additional guidance
Accept any equivalent fraction, decimal form 0.7 or percentage form 70%
| Answer | Mark | Mark scheme |
|---|---|---|
| 45 | P1 | for start to process, eg \(30 \div 2\ (= 15)\) |
| A1 | cao |
| Answer | Mark | Mark scheme |
|---|---|---|
| No with reason | C1 | for No with reason or ft (b) Acceptable examples the number of red and yellow counters is an odd number 25 cannot be divided by 2 to give a whole number You can’t have half a counter You can’t split it evenly Not acceptable examples Yes ….. they are in the ratio 2 : 3 one must be more than the other |
Additional guidance
If the reason is supported by numerical evidence then that evidence must be accurate.
can ft (b)
Note: if the answer to part (b) is an even number then ‘yes’ with supporting evidence is an acceptable answer