Foundation June 2024 Paper 2 Q8
8 There are 56 cubes in a box.
The cubes are green, red, blue or white.
17 cubes are green.
There are an equal number of red, blue and white cubes.
(a) How many red cubes are in the box? [2 marks]
(b) 24 more cubes are added to the box.
A cube is picked at random.
The probability that the cube is green is 0.4
How many of the 24 cubes added to the box are green? [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(56 - 17\) or 39 | M1 | |
| 13 | A1 |
Additional guidance
| M1 may be awarded for correct work with no answer or incorrect answer, even if this is seen in multiple attempts | |
| Ignore any values for blue or white cubes | |
| eg G B W R 17 13 13 13 With R unambiguously linked with 13 May be seen as a ratio Unless contradicted on the answer line is awarded M1A1 | |
| 17 (\(+\)) 13 (\(+\)) 13 (\(+\)) 13 without 13 linked to red | M1A0 |
| 13 and answer 13 out of 56 | M1A1 |
| 13 and answer \(\dfrac{13}{56}\) | M1A0 |
| 13 and answer 56 | M1A0 |
| Answer \(\dfrac{13}{56}\) | M1A0 |
| Answer | Mark | Comments |
|---|---|---|
| \(56 + 24\) or 80 | M1 | |
| \(0.4 \times\) their 80 or 32 | M1dep | oe eg \(0.4 \times 56 + 0.4 \times 24\) or \(9.6 + 22.4\) |
| 15 | A1 |
Additional guidance
| M1 may be awarded for correct work with no answer or incorrect answer, even if this is seen in multiple attempts | |
| 15 and answer 15 out of 24 | M1M1A1 |
| 15 and answer \(\dfrac{15}{24}\) or \(\dfrac{3}{8}\) | M1M1A0 |
| Answer \(\dfrac{15}{24}\) | M1M1A0 |
| 80 seen embedded in a fraction | M1 |
| Answer \(\dfrac{3}{8}\) with no other creditworthy work | M0M0A0 |
| Condone \(80 \times 40\%\) | M1M1 |
| 40% of 80 is 2nd M0 unless recovered | |
| Build up methods for finding 40% of 80 must be completed to be awarded the M mark eg 80 followed by 10% \(= 8\) and \(4 \times 8 = 32\) eg \(0.1 \times 80 = 6\) and \(4 \times 6 = 24\) eg 80 followed by 10% \(= 6\) and \(4 \times 6 = 24\) | M1M1 M1M1 M1M0 |